Observing reproduction and inheritance in Reebopsus imaginarius


            In this activity, we will observe meiosis, fertilization, development and birth of a baby Reebop (Reebopsus imaginarius) . Reebops have 16 chromosomes (2n=16) and 8 different traits are controlled by 8 different genes on those chromosomes.


Procedure:

1. You should have two envelopes, each with a set of chromosomes. Take the maternal chromosomes out and use the information in Table 1 to complete Table 2.


Table 1: Allele key

Antennae

AA 2 antennae

Aa 2 antennae

aa no antennae

Body segments

BB 3 body segments

Bb 3 body segments

bb 2 body segments

Tail

TT curly

Tt curly

tt straight

Nose

NN red nose

Nn orange nose

nn yellow nose

Legs

LL blue legs

Ll blue legs

ll red legs

Sex

XX female

Xy male

 

Eyes

EE 2 eyes

Ee 2 eyes

ee one eye

Humps

HH 1 hump

Hh 1 hump

hh 3 humps


Table 2: Parental genotypes and phenotypes

Trait

Mom’s Genotype

Mom’s Phenotype

Dad’s genotype

Dad’s phenotype

Antennae

 

 

 

 

Body segments

 

 

 

 

Tail

 

 

 

 

Nose

 

 

 

 

Legs

 

 

 

 

Sex

 

 

 

 

Eyes

 

 

 

 

Humps

 

 

 

 


2. Do the same for the paternal chromosomes.

3. Now turn the chromosome cards face down, so that you cannot see the genotypes (letters) on them. Line up the chromosomes into Mom Reebop’s chromosomes (pink) and Dad Reebop’s chromosomes (blue).

4. Randomly take one chromosome of each pair from the Mom’s chromosomes and place in the ‘female gamete’ pile. Repeat for each pair of the Dad’s chromosomes and place them in the ‘male gamete’ pile.

a) What process did you just model? How many chromosomes does each gamete have?

5. Now mix the female gamete and male gamete piles to form a ‘baby chromosome’ pile.

b) What process did you just model? How many chromosomes does the zygote have?

6. Put the remaining chromosomes back into the envelopes.


You have now carried out sexual reproduction, whereby half the chromosomes from one parent have been randomly mixed with half from the other parent to make a unique combination. Note that each parent donated half the chromosome number (eight) that the adult cells contain (i.e. 16). Meiosis is responsible for halving the chromosome number in gametes so that when gametes combine at fertilization, the correct number is present in the new individual.


7. Complete Table 3 for your baby Reebop.


Table 3: Baby genotype and phenotype

Trait

Allele from Mom

Allele from Dad

Baby’s Phenotype

Antennae

 

 

 

Body segments

 

 

 

Tail

 

 

 

Nose

 

 

 

Legs

 

 

 

Sex

 

 

 

Eyes

 

 

 

Humps

 

 

 


c) What kind of inheritance governs nose color? How can you tell? (Hint: Look at the heterozygote)


Sexual reproduction accomplishes a very important purpose and that is to increase diversity.

d) What do you notice about the features that your baby has? Is it identical to either parent?

e) Compare your baby to that of other groups. Are there any babies that are identical?

f) Are any babies the same as their parents?

g) How much genetic material does each parent provide?

h) What are the advantages of increased diversity in a population?